Gravitational field — combining M = ρV with g = GM/R² (multi-step)
“This was a challenging question which required several steps. Errors were often made when finding the mass of Mars using the data given and in using the equation for g on the surface of Mars.”
Choose a radius and density, then read the chain: R → V → M → g. The bar compares surface gravity with Earth’s.
Because M = ρ(4/3)πR³, the R³ on top and R² below leave g = (4/3)πGρR — linear in R. That is why the diameter mistake exactly doubles the answer.
Original reconstruction inspired by the misconceptions described in the Singapore-Cambridge GCE A-Level H1 Physics 8867 November 2023 Examiner Report. Not the actual examination question. For classroom exploration.
Made by lookang, using Claude Fable 5. More resources: iwant2study.org