Kinematics — applying equations of motion to a displacement–time graph
“The most common incorrect answer… implies that those candidates who got it wrong did not realise that they had to use the equations of motion and apply them to the graph. It may be that they confused it with a v–t graph.”
One motion (a = 1.0 m s−2 from rest), two views. Drag the time slider and switch graphs. Note what the gradient means on each.
The curve and the straight line describe the same motion. Gradient of s–t = velocity; gradient of v–t = acceleration; area under v–t = displacement.
Original reconstruction inspired by the misconceptions described in the Singapore-Cambridge GCE A-Level H1 Physics 8867 November 2023 Examiner Report. Not the actual examination question. For classroom exploration.
Made by lookang, using Claude Fable 5. More resources: iwant2study.org